how to solve quadratic equations

Let us learn how to solve quadratic equations.

Problem 1.

Solve the quadratic equations: x² – x – 132 = 0

Solution:

We find –132 = (–12) × (11), (–12) + 11 = –1.

Hence we get x² – x – 132 = [x + (–12)] (x + 11) = (x – 12) (x + 11)=0

X= 12, -11

Problem 1:

Solve the equation: 15 – 2x – x²=0

Solution:

Writing in the standard form,

15 – 2x – x² = –x² – 2x + 15

= (–1) (x² + 2x – 15).

Here, we find –15 = 5 × –3, 5 + (–3) = 2

Hence, we get 15 – 2x – x² = (–1) [(x+5) {x + (–3)}]

(–1) (x +5)(x – 3) = 0

(x + 5) (3 – x). = 0

X= -5,-3

In our next blog we shall learn about functions of the skeletal system I hope the above explanation was useful.Keep reading and leave your comments.